b^2-19b+70=0

Solution for b^2-19b+70=0 equation:

Simplifying
b2 + -19b + 70 = 0

Reorder the terms:
70 + -19b + b2 = 0

Solving
70 + -19b + b2 = 0

Solving for variable 'b'.

Factor a trinomial.
(5 + -1b)(14 + -1b) = 0

Subproblem 1
Set the factor '(5 + -1b)' equal to zero and attempt to solve:

Simplifying
5 + -1b = 0

Solving
5 + -1b = 0

Move all terms containing b to the left, all other terms to the right.

Add '-5' to each side of the equation.
5 + -5 + -1b = 0 + -5

Combine like terms: 5 + -5 = 0
0 + -1b = 0 + -5
-1b = 0 + -5

Combine like terms: 0 + -5 = -5
-1b = -5

Divide each side by '-1'.
b = 5

Simplifying
b = 5
Subproblem 2
Set the factor '(14 + -1b)' equal to zero and attempt to solve:

Simplifying
14 + -1b = 0

Solving
14 + -1b = 0

Move all terms containing b to the left, all other terms to the right.

Add '-14' to each side of the equation.
14 + -14 + -1b = 0 + -14

Combine like terms: 14 + -14 = 0
0 + -1b = 0 + -14
-1b = 0 + -14

Combine like terms: 0 + -14 = -14
-1b = -14

Divide each side by '-1'.
b = 14

Simplifying
b = 14
Solution
b = {5, 14}